(16, 40)

A = 16

B = 40

Sum 56
Difference 24
A × B 640
A ÷ B 0.4
B ÷ A 2.5
GCD 8
LCM 80
Average 28

Sum of squares

1856

\[ 16^2 + 40^2 = 1856 \]

Norm

$\sqrt{ 16^2 + 40^2 } = 43.08131845707603$

Geometric mean

25.298221281347036

(16, 40) is amicable?

No

Properties of 16 and 40

Properties of 16 and 40: The GCD and LCM of 16 and 40 are 8 and 80 respectively. 16 + 40 = 56, |16 - 40| = 24, 16 * 40 = 640, 16 / 40 = 0.4, 40 / 16 = 2.5. The average of 16 and 40 is 28 and the norm of them is 43.08131845707603. The geometric mean of two numbers is 25.298221281347036.